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Q1.. Using prime factorization, find the H.C.F and L.C.M of 72, 126 and 168. Also show that H.C.F Х L.C.M ≠ Product of the three numbers.
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Class 10th,
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Heya !!
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PRIME FACTORIZATION OF 72 = 2 × 2 × 2 × 3 × 3
PRIME FACTORIZATION OF 126 = 2 × 3 × 3 × 7
PRIME FACTORIZATION OF 168 = 2 × 2 × 2 × 3 × 7
H.C.F of 72, 126, and 168 = 2 × 3 = 6
L.C.M of 72, 126, and 168 = 2 × 3 × 2 × 2 × 3 × 3 × 7 = 1512.
Product of three numbers = 72 × 126 × 168 = 1524096.
whereas,
Product of H.C.F and L.C.M = 1512 × 6 = 9072
Hence,
Product of three numbers is not equal to product of their L.C.M and H.C.F
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Hope it helps.....
with regards...
@vaibhav246
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PRIME FACTORIZATION OF 72 = 2 × 2 × 2 × 3 × 3
PRIME FACTORIZATION OF 126 = 2 × 3 × 3 × 7
PRIME FACTORIZATION OF 168 = 2 × 2 × 2 × 3 × 7
H.C.F of 72, 126, and 168 = 2 × 3 = 6
L.C.M of 72, 126, and 168 = 2 × 3 × 2 × 2 × 3 × 3 × 7 = 1512.
Product of three numbers = 72 × 126 × 168 = 1524096.
whereas,
Product of H.C.F and L.C.M = 1512 × 6 = 9072
Hence,
Product of three numbers is not equal to product of their L.C.M and H.C.F
____________________________
Hope it helps.....
with regards...
@vaibhav246
Anonymous:
thanks..:)
my pleasure.... ☻
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