Question

Hey what a funny question
Ans konw the ans to the question
(only if u know)​

Answer 1

Step-by-step explanation:

the answer is 10 . hope it helps

Answer 2

Question

Solve ⇒ $\sf (\dfrac{2}{5})^{-3} \times (\dfrac{5}{4})^{-2}$

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Answer

To solve this we must apply laws of exponents. First of all we must simplify 4 to 2².

⇒ $\sf (\dfrac{2}{5})^{-3} \times (\dfrac{5}{4})^{-2}$

⇒ $\sf (\dfrac{2}{5})^{-3} \times (\dfrac{5}{2^{2}})^{-2}$

Now we will apply this law of exponent ⇒ $a^{-m}=\frac{1}{a^{m}}$

⇒ $\sf (\dfrac{2}{5})^{-3} \times (\dfrac{5}{2^{2}})^{-2}$

⇒ $\sf (\dfrac{5}{2})^{3} \times (\dfrac{2^{2}}{5})^{2}$

Now we shall apply this law of exponent ⇒ $(a^{m})^{n}=a^{m\times n}$

⇒ $\sf (\dfrac{5}{2})^{3} \times (\dfrac{2^{2}}{5})^{2}$

⇒ $\sf (\dfrac{5}{2})^{3} \times (\dfrac{2^{4}}{5^{2}})$

Now we will apply this law of exponent ⇒ $(\frac{a}{b})^{m} = \frac{a^{m}}{b^{m}}$

⇒ $\sf (\dfrac{5}{2})^{3} \times (\dfrac{2^{4}}{5^{2}})$

⇒ $\sf \dfrac{5^{3}}{2^{3}} \times \dfrac{2^{4}}{5^{2}}$

Now we shall apply these laws of exponents ⇒ $a^{m}\times a^{n} = a^{m+n}$ and $a^{m}\div a^{n} = a^{m-n}$

⇒ $\sf \dfrac{5^{3}}{2^{3}} \times \dfrac{2^{4}}{5^{2}}$

⇒ $\sf 5^{3-2}\times 2^{4-3}$

⇒ $\sf 5^{1}\times 2^{1}$

⇒ $\sf 10$

$\bf\therefore (\dfrac{2}{5})^{-3} \times (\dfrac{5}{4})^{-2}=10$

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