Question

Heya
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1. How many atoms of Na, C and O are present in 0.5 mole of Na2CO3 ?


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Answer 1

1 mole Na2CO3 equivalent to 6.022×10^23 no of Na2CO3 molecules
so in 0.5 mole Na2CO3 there is 3.011×10^23 no of Na2CO3 molecules.

each Na2CO3 molecule contains 2 Na atoms , 1 C atom and 3 O atoms.

so in 0.5 mole Na2CO3
the no of Na atom is 3.011×10^23×2=6.022×10^23

the no of C atom is 3.011×10^23×1=3.011×10^23

the no of O atom is 3.011×10^23×3=9.033×10^23

Answer 2

1 mole(106g) NA2CO3= 6.022*10²³ molecules

therefore, 1g=6.022*10²³/106

Of 6 atoms=6.022*10²³/106*6 atoms