heya @!!!!!●●●●●●●●●
FRIENDS PLZZZ SOLVE THIS QUESTION FOR ME ❤♡♡☆☆☆☆☆☆☆
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area of one piece
s= (50 + 20 + 50)/2 = 120/2 = 60
√s(s-a)(s-b)(s-c)
= √60(60-50)(60-20)(60-50)
√60 x 10 x 40 x 10
= √6 x 10 x 10 x 4 x 10 x 10
= 200√6
area of 12 pieces = 12 x 200√6 = 2400√6
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hey there ?!!
the triangle sides are given as (50, 20, 50 cm ) which means it is an isosceles ∆ .
now ,
we know that Lome drawn from the vertex of an isosceles triangle is perpendicularly to its opposite side .
so ,
height of the traingle = ab² + bo²
ac² = 50²+10²
ac² = 2500+100
ac² = 2600
ac = √2600 = 50.99...
now , area of ∆ = 1/2×b×h = 1/2 × 20×50.99
area of ∆ = 10×50.99 = 509.99cm²
now ,
area of umbrella = no. of triangular pieces × area if ∆
area of cloth to make umbrella = 12 × 509.99 = 6119.99 cm²
hence the area of the cloth stiching the
umbrella = 6119.99cm²
hope it helps !
be brainly ♥
the triangle sides are given as (50, 20, 50 cm ) which means it is an isosceles ∆ .
now ,
we know that Lome drawn from the vertex of an isosceles triangle is perpendicularly to its opposite side .
so ,
height of the traingle = ab² + bo²
ac² = 50²+10²
ac² = 2500+100
ac² = 2600
ac = √2600 = 50.99...
now , area of ∆ = 1/2×b×h = 1/2 × 20×50.99
area of ∆ = 10×50.99 = 509.99cm²
now ,
area of umbrella = no. of triangular pieces × area if ∆
area of cloth to make umbrella = 12 × 509.99 = 6119.99 cm²
hence the area of the cloth stiching the
umbrella = 6119.99cm²
hope it helps !
be brainly ♥
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