mass of sodium in 53 gram of Na2CO3 is?
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given wt. of Na2CO3=53g
molar mass of Na2CO3=23*2+12+16*3
=106
NOW NO. OF MOLES n=wt. in grams/molar mass
=53/106
=0.5 moles
Now we know that 53g of Na2CO3 contains 0.5 moles of Na
No. of atoms of Na =6.022*1023 * 0.5
=3.011*1023
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