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HELP PLEASE
QUESTION:-
if cosec theta+sin theta =4 find the value of (sin²theta+cosec²theta)
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sinθ+cosecθ=2
⟹sinθ+ (1/ sinθ) = 2
squaring on both sides
(sinθ+ 1/sinθ )²=4
⟹sin²θ+ 1/sin²θ+2(sinθ)(1/sinθ)=4
⟹sin²θ+1/sin²θ+2=4
⟹sin²θ+ 1/sin²θ =2
⟹sin²θ+cosec² θ=2
..hence proved..
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