Chemistry, asked by Mahak01, 11 months ago

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calculate the number of water molecules present in 1ml of water:-


ravi9848267328: 3.3*10^22
ravi9848267328: hey whts the ans then

Answers

Answered by Anonymous
1

One mole of water has a mass of 18 grams and a volume of 18 mL (as the density of water is 1 g per cm3). It contains Avogadro's number of molecules (6x 10^23). Thus 1 litre of water contains 1 / 18 x 1000 x 6 x 1^23 molecules (assume you can do the maths…)

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Answered by ravi9848267328
0

Answer:

Explanation:

, we have molecular mass of water H2O

= 1x2 + 16 = 18 gm

Since, 1 mol water = molecular mass

in gm = 18gm.

As no. of molecules = no. of moles x

avogadro's no. 6.022 x 10^23

And No. of moles = given mass/

molecular mass.

Here, given mass = 1ml= 1gm

Thus, no. of moles of water in 1 ml =

1/18 mol.

And so No. of molecules in 1ml water

= no. of moles x avogadro's no. = 1/18  X =0.33 x

1023 molecules

So, the no. of molecules of water in

1ml of water = 3.3 x 10^22

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