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calculate the number of water molecules present in 1ml of water:-
ravi9848267328:
3.3*10^22
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One mole of water has a mass of 18 grams and a volume of 18 mL (as the density of water is 1 g per cm3). It contains Avogadro's number of molecules (6x 10^23). Thus 1 litre of water contains 1 / 18 x 1000 x 6 x 1^23 molecules (assume you can do the maths…)
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Answer:
Explanation:
, we have molecular mass of water H2O
= 1x2 + 16 = 18 gm
Since, 1 mol water = molecular mass
in gm = 18gm.
As no. of molecules = no. of moles x
avogadro's no. 6.022 x 10^23
And No. of moles = given mass/
molecular mass.
Here, given mass = 1ml= 1gm
Thus, no. of moles of water in 1 ml =
1/18 mol.
And so No. of molecules in 1ml water
= no. of moles x avogadro's no. = 1/18 X =0.33 x
1023 molecules
So, the no. of molecules of water in
1ml of water = 3.3 x 10^22
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