Question

Heya❤❤

(◍•ᴗ•◍)

Find the sum

31+33+35+37+.......+133

​

Answer 1

The series forms an Arithmetic progression where,

a=30 and d=2

The sum of the first 'n' terms of an A.P. is given by the formula:

S=(n/2)*(a+l), where l=last term

'n' can be calculated using:

nth term=a+(n-1)d

thus, 133=31+(n-1)*2

On solving we get n=52

On substituting in the original formula, we get:

S=(52/2)*(31+133)

=26*164

=4264

Answer 2

❤♣️HËŁŁØ MÃŤÉ♣️❤

a=31

d=2

an=133

an=a+(n-1)d

133=31+(n-1)2

133=31+2n-2

133=29+2n

133-29=2n

104=2n

n=104/2

n=52

Sn=n/2(a+an)

=52/2(31+133)

=26(164)

=4,264

$\huge\mathfrak{Answer=4,264}$