heya folk
help me
answer is 210
Attachments:
Answers
Answered by
1
Heya folk !!
Here's the answer you are looking for
In the ∆PQR,
<PQR = (180 - x)° (linear pairs)
<PRQ = (180 - y)° (linear pairs)
Apply angle sum property in ∆PQR,
<PQR + <PRQ + <QPR = 180°
180° - x + 180° - y + 30° = 180°
x + y = 180° + 180° + 30° - 180° = 210°
☛Therefore, x + y = 210°
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
In the ∆PQR,
<PQR = (180 - x)° (linear pairs)
<PRQ = (180 - y)° (linear pairs)
Apply angle sum property in ∆PQR,
<PQR + <PRQ + <QPR = 180°
180° - x + 180° - y + 30° = 180°
x + y = 180° + 180° + 30° - 180° = 210°
☛Therefore, x + y = 210°
★★ HOPE THAT HELPS ☺️ ★★
Deekshii1:
thq a lot
no issues :-)
Similar questions