Question

HEYA, FRIEND'S---------------❤✌

SOLVE THIS........❤

Six years ago the mother's age was about the same age as the child's age. At the age of three years of age, the mother's age will be three times the age of the child. Take out the present age of the mother and the child.

ONLY ANSWER .... PLZZ----------❤​

Answer 1

Hello.....Kem Cho?

Suppose, the age of the son six year before was x

∴ mother’s age six year before was x2

∴ present age of the son is (x + 6) and

present age of the mother is (x2

+ 6)

Three years hence, son’s age will be (x + 9) and mother’s age will

be (x2 + 9) ..

by given condition,

x2 + 9 = 3(x + 9)

∴ x2 - 3x + 9 - 27 = 0

∴ x2 - 3x - 18 = 0

∴ (x - 6) (x + 3) = 0

∴ x = 6 or x = -3

But age cannot be negative ∴ x ≠ -3

∴ son’s present age = x + 6 = 6 + 6 = 12 years.

mother’s present age = x2

+ 6 = 36 + 6 = 42 years........

Answer 2

Step-by-step explanation:

Let age of son 6 years before be x

then mother's age = x

2

then, persent age son =x+6

mothers age =x

2

+6

After 3 year,

son =x+6+3=x+9

mother =x

2

+6+3=x

2

+9

A.T.Q

x

2

+9=3(x+9)

x

2

+9=3x+27

x

2

−3x−18=0

x

2

−6x+3x−18=0

x(x−6)+3(x−6)=0

(x+3)(x−6)=0

x=6 (-3 will neglect)

Persent age of mother = x

2

+6⇒36+6=42

Son = x+6=6+6=12