heya !!!
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FRIENDS PLZZZ SOLVE THIS QUESTION FOR ME
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Area Of Rhomus = 1/2*d1*d2
Here d1 = 48 cm
1/2*48*d2 = 480
24d2 = 480
d2 = 480/24 = 20cm
ii) Diagonals Of A Rhombus Intersect Each Other At Right Angles And Bisect Each Other.
So In Rhombus ABCD
AC = BD
Let The Mid Point Of Intersection Be O.
AO = CO
And BO = DO
AO = 1/2*48 = 24
BO = 1/2*20 = 10
Now They Form A Right Triangle
Side^2 = 24^2+10^2
Side^2 = 576+100 = 676
Side = 26 cm
iii)Perimeter Of Rhombus = 4*26 = 104cm
Here d1 = 48 cm
1/2*48*d2 = 480
24d2 = 480
d2 = 480/24 = 20cm
ii) Diagonals Of A Rhombus Intersect Each Other At Right Angles And Bisect Each Other.
So In Rhombus ABCD
AC = BD
Let The Mid Point Of Intersection Be O.
AO = CO
And BO = DO
AO = 1/2*48 = 24
BO = 1/2*20 = 10
Now They Form A Right Triangle
Side^2 = 24^2+10^2
Side^2 = 576+100 = 676
Side = 26 cm
iii)Perimeter Of Rhombus = 4*26 = 104cm
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