Question

Heya Friends ♡♥

Solve the following equation when the value of x=
$\frac{ - 1}{2}$
Equation=
$\frac{2x - 1}{3} - \frac{6x - 2}{5}$
❌❌NO SPAM❌❌
✅✅✅PLEASE GIVE CORRECT ANSWER✅✅✅

​

Answer 1

(13/15) is answer

Step-by-step explanation:

put value of x in given eq.

(1) 2x/3-1/3-6x/5-2/5

(2) 2 (-1/2)/3-1/3-6 (-1/2)/5-2/5

(3) -1/3-1/3+1/5-2/5

(4) By taking L.C.M: (-5-5+3-6)/15

(5) (-10+3-6)/1505

(6)by solve it answer is ; 13/15

Answer 2

$\bold{\underline {\red{Method \:1}}}$

⇒ $\sf{\dfrac{2x\:-\:1}{3}}\:-\:\dfrac{6x\:-\:2}{5}$

Now, take LCM.

LCM of 3 and 5 is 15.

⇒ $\sf{\dfrac{5(2x\:-\:1) \: - \: 3(6x \: - \: 2)}{15}}$

⇒ $\sf{\dfrac{10x\:-\:5 \: - \: 18x \: + \: 6}{15}}$

⇒ $\sf{\dfrac{-\:8x\: +\: 1}{15}}$ ___ (eq 1)

Also, we have given in question that, x = -1/2

Substitute value of x = -1/2 in (eq 1)

⇒ $\sf{\dfrac{-\:8(\frac{-1}{2})\:+\:1}{15}}$

⇒ $\sf{\dfrac{(\frac{8}{2})\:+\:1}{15}}$

⇒ $\sf{\dfrac{4\:+\:1}{15}}$

⇒ $\sf{\dfrac{5}{15}}$

⇒ $\sf{\dfrac{1}{3}}$

•°• If we put value of x = -1/2 in (2x - 1)/3 - (6x - 2)/5 we get 1/3.

$\bold{\underline {\red{Method \:2}}}$

Given equation is $\sf{\dfrac{2x\:-\:1}{3}\:-\:\dfrac{6x\:-\:2}{5}}$

Substitute value of x = -1/2 in given equation

=> $\sf{\dfrac{2(\frac{-1}{2})\:-\:1}{3}\:-\:\dfrac{6(\frac{-1}{2})\:-\:2}{5}}$

=> $\sf{\dfrac{-\:1\:-\:1}{3}\:-\:\dfrac{-\:3\:-\:2}{5}}$

=> $\sf{\dfrac{-\:2}{3}\:-\:\dfrac{-\:5}{5}}$

Take LCM of 3 and 5 i.e. 15

=> $\sf{\dfrac{-\:10\:+\:15}{15}}$

=> $\sf{\dfrac{5}{15}}$

=> $\sf{\dfrac{1}{3}}$

•°• If we put value of x = -1/2 in (2x - 1)/3 - (6x - 2)/5 we get 1/3.