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Help Needed in the question below ⬇️⬇️✌️
The sides of a triangle are 42 CM 34 cm and 20 CM . Calculate its area and the length of the height on the longest side.
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omkar270177:
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♄€☈€ ♗ⓢ ☋☈ ꍏ♫ⓢω€☈.
- Area of triangle = √S(S - a ) (S - b ) (S - c ).
Where,
S = Semi perimeter.
And a , b , c are sides of triangle.
So .
- S = ( a+b+c)/2
= (42 + 34 + 20 )/2 = 96/2 = 48 cm.
Area = √48 ( 48 - 42 ) (48 - 34 ) ( 48 - 20 )
= √ 48 × 6 × 14 × 28
= √ 112896 = 336 cm².
- With the help of longer side
Area = 1/2 × Base × Height
= 1/2 x 42 x Height
= 21 × Height .
A/Q , 21 × Height = 336
⇒ Height = 336/21
∴ Height = 16 cm.
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2
Answer:
16 cm...................................
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