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Question-
Find the position of final image after 3 successive reflections taking first reflection on M1.
Please refer the above attachment for the diagram..
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The position of final image after 3 successive reflections is 5.5 cm.
Explanation:
The lens formula is given as:
1/f = 1/u + 1/v
Where,
f = Focal length
u = Object distance
v = Image distance
Now, the radius of curvature (R) and focal length is given as:
f = R/2 = 20/2 = 10 cm
Focal length of concave lens = -10 cm
First reflection:
f = -10 cm and u = - 15 cm
On substituting the values on lens formula, we get,
-1/10 = -1/15 + 1/v
1/v = -1/10 + 2/15 ⇒ 1/v = 1/30
∴ v = 30 cm
Second reflection: (reflection is from concave mirror)
f = 20/2 = 10 cm and u = 55 cm
1/10 = 1/55 + 1/v
1/v = 1/10 - 1/55 ⇒ 1/v = 9/110
∴ v = 110/9 = 12.2 cm
Third reflection: (reflection is from convex mirror)
f = 10 cm and u = -12.2 cm
1/10 = -1/12.2 + 1/v
1/v = 1/10 + 1/12.2 ⇒ 1/v = 111/610
∴ v = 610/111 = 5.5 cm
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