Math, asked by yana85, 1 year ago

HEYA!!!!!


HELP ME IN THIS QUESTION

●_●●_●●_●●_●●_●

Attachments:

yana85: Thanks pranav
imperialxak47: please can you give me the ans of my last asked question.
yana85: Maths hai kya????
imperialxak47: yes
yana85: Nhi aati sorry
yana85: It's like phobia for ms
yana85: me
imperialxak47: can you see it for 1 time ..
imperialxak47: plz
yana85: Ok

Answers

Answered by imperialxak47
3

This gives : 1/p + 1/q = 1/(p+q+x) - 1/x 

=> (q+p) / (pq) = {x - (p+q+x)} / {(p+q+x).x} 

=> (p+q) / (pq) = - (p+q) / {(p+q+x).x} 

=> 1/(pq) = -1 / {(p+q+x).x} ( since, p+q ≠ 0 ) 

=> (p+q+x).x = - pq 

=> px +qx + x^2 + pq = 0 

=> x^2 + px + qx + pq = 0 

=> x ( x + p ) + q ( x + p ) = 0 

=> ( x + p ) . ( x + q ) = 0 

=> x + p = 0 OR x + q = 0 

if it help you then plz mark it as brainliest.


yana85: no problem
imperialxak47: my last question??
yana85: Mila hi nhi???
imperialxak47: can I post it again
yana85: Vo koi aur de rha h ans.
yana85: ok
imperialxak47: koi sahi nahi bata raha
yana85: Oh! ¡!!!
imperialxak47: can you try now I have post it again.
yana85: Ok
Answered by shivasai75433
0

Answer:

hi check my b.io and fol.low me

Similar questions