heya !! in the figure given above , AB || DE and BD || EF.prove that DC^2 = CF × AC.
◆EXPECTING CORRECT ANSWER.
#CH- SIMILARITY( class 10th ).
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In ΔABC, we have CD/DA = CE/EB as AB || DE
in ΔCDB, we have CF/FD = CE/EB as EF || BD
hence we get CD/DA = CF/FD
=> Reciprocals: DA/CD = FD /CF
=> Add 1 on both sides: AC /CD = DC/CF
=> DC^2 = CF * AC
in ΔCDB, we have CF/FD = CE/EB as EF || BD
hence we get CD/DA = CF/FD
=> Reciprocals: DA/CD = FD /CF
=> Add 1 on both sides: AC /CD = DC/CF
=> DC^2 = CF * AC
Anonymous:
thnx a lot
welcome!
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