Question

HEYA...... KARTIK HERE
.
.
.


.
.
.
#NEED FULL EXPLANATION★
# 20 POINTS★
#NO SPAMS PLEASE★

◆3 and 4

______________________

Thank you

Answer 1

$\bold{\underline{Solution:}}$

3) As it is 400, which is a perfect square.

So, the square root of 400 is 20.

Now, we will find the last two digits of 3^20.

=> (3^5)^4

=> 3^5 = 243

=> (243)^4 = (243^2) × (243^2)

=> (243^2) = 59049

=> 59049 × 59049= 3486784401

It ends at 01 ,

Now , on squaring

1^2 = 1

So, the last two digits of 3^400 are $\textbf{01}$

$\bold{\boxed{Thank you!!}}$

Answer 2

Answer:

thanks for the free points broooooooooo