Question

Heya Mate

Pikaachu needs a help :p

IRODOV 1.178

What I'm doing is :

-> Write dp = F.dt

-> Write the change in momentum and ... substitute the above relation and get the Answer Correct !

-> However friends =_= Me here confused why and how can we take ( u ) relative to the rocket as ( u + v + dv ) as I mentioned in the Equation

-> Note that it works..

Please clear my doubt ^^"

Answer 1

$\texttt{Hello}$



Let a certain time of moment t and the rocket has mass m and velocity v . This velocity v is relative to reference frame . And now we will consider inertial frame .



In this reference frame we will take our momentum that the rocket has acquired during the time dt .



$\bold{dp = mdv + \mu dt u = Fdt}$


$\bold{m \frac{dv}{dt} = F - \mu u}$



$\bold{mw = F - \mu u}$



H.P