Question

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Answer 1

Hey mate!!!!

lim (x→0) [ sin ( π cos² x ) ] / x²  

= lim (x→0) { sin [ π ( 1 - sin² x ) ] } / x²  

= lim (x→0) [ sin ( π - π sin² x ) ] / x²  

= lim (x→0) [ sin ( π sin² x ) / x²  

= lim (x→0) [ ( π sin² x ) / x² ] ....................... from (1)  

= π • [ lim (x→0) ( (sin x) / x ) ]²  

= π • [ 1 ]²  

= π ........................................... Ans.

Ans---- Option A

Hope this helps you!!!

Answer 2

Step-by-step explanation:

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