heya mate
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Hey mate!!!!
lim (x→0) [ sin ( π cos² x ) ] / x²
= lim (x→0) { sin [ π ( 1 - sin² x ) ] } / x²
= lim (x→0) [ sin ( π - π sin² x ) ] / x²
= lim (x→0) [ sin ( π sin² x ) / x²
= lim (x→0) [ ( π sin² x ) / x² ] ....................... from (1)
= π • [ lim (x→0) ( (sin x) / x ) ]²
= π • [ 1 ]²
= π ........................................... Ans.
Ans---- Option A
Hope this helps you!!!
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