Math, asked by muskan55794, 1 year ago

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Answers

Answered by siddhartharao77
13

Given Equation is (x + 4)^2 - 5xy -20y - 6y^2

= > x^2 + 8x + 16 - 5xy - 20y - 6y^2

= > x^2 + 4x + 4x + 16 + xy - 6xy + 4y - 24y - 6y^2

= > x^2 + xy + 4x - 6xy - 6y^2 - 24y + 4x + 4y + 16

= > x(x + y + 4) - 6y(x + y + 4) + 4(x + y + 4)

= > (x - 6y + 4)(x + y + 4).

Hope this helps!


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Answered by MOSFET01
9
solution for question
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