Question

heya mates i am resendi please help me and do all ques that u seeee​

Answer 1

Step-by-step explanation:

1.

the degree of zero polynomial is not defined but we define it as 0

2.

in one variable :-

${x}^{27} + 8{x}^{3} + 3$

in three variable :-

${x}^{27} + {y}^{5} + {z}^{3}$

3.

see attached for answer if this question

so by dividing remainder = -10X-3

and quotient=3X³-5X²+10X

4.

x+2 is a factor of given polynomial

so x+2=0

x=-2 put in given polynomial

p(x)=p(-2)=>0

a(-2)⁴+2(-2)³-3(-2)²+b(-2)-4=0

16a-16-12-2b-4=0

16a-2b=32

8a-b=16----(1)

and x-2 is also it's factor

so ,

p(x)=p(2)=>0

a(2)⁴+2(2)³-3(2)²+b(2)-4=0

16a+16-12+2b-4=0

16a+2b=0

8a+b=0---(2)

by solving (1) and (2)

we get,

a=1 and b=-8

$<font face="comics sans MS" color="#EE2A44"><h1><marquee>FOR DOUBT JUST COMMENT </marquee></h1></font>$