Question

HEYA
.
.
.

.
. .
Need explanation
No spams
15 POINTS

Answer 1

$Given : |x - 1| + |x - 2| + |x - 3| \geq 6$

(1) x < 1

$= \ \textgreater \ -(x - 1) - (x - 2) - (x - 3) \geq 6$

$= \ \textgreater \ -x + 1 - x + 2 - x + 3 \geq 6$

$= \ \textgreater \ - 3x + 6 \geq 6$

$= \ \textgreater \ -3x \geq 0$

$= \ \textgreater \ x \leq 0$


(2) $1 \leq x \ \textless \ 2$

$= \ \textgreater \ x - 1 - (x - 2) - (x - 3) \geq 6$

$= \ \textgreater \ x - 1 - x + 2 - x + 3 \geq 6$

$= \ \textgreater \ -x \geq 2$

$= \ \textgreater \ x \leq -2$




(3) $2 \leq x \ \textless \ 3$

$= \ \textgreater \ x - 1 + x - 2 - (x - 3) \geq 6$

$= \ \textgreater \ x - 1 + x - 2 - x + 3 \geq 6$

$= \ \textgreater \ x \geq 6$



(4) $x \geq 3$

$= \ \textgreater \ x - 1 + x - 2 + x - 3 \geq 6$

$= \ \textgreater \ 3x - 6 \geq 6$

$= \ \textgreater \ 3x \geq 12$

$= \ \textgreater \ x \geq 4$


Therefore, the answer is option(C).

Hope this helps!

Answer 2

Answer:

HEY

Step-by-step explanation:

.

.................