Question

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PLZ. ...HELP ME IN THIS QUESTION

Answer 1

First we know the HCF of both number

408 =2×2×2×3×17

1032=2×2×2×3×43

hence the HCF is

2×2×2×3=24

ATQ

$1032m - 408 \times 5 = 24 \\ 24(43m - 17 \times 5) = 24 \\ 43m - 85 = 1 \\ 43m = 1 + 85 \\ 43m = 86 \\ m = \frac{86}{43} \\ m = 2$

the value of m will be 2

Answer 2

If the HCF of 408 and 1032 can be written as 

By Euclid 's division algorithm,

1032 = 408×2 + 216

408 = 216×1 + 192

216 = 192×1 + 24

192 = 24×8 + 0

Since the remainder becomes 0 here, so HCF of 408 and 1032 is 24

Now, 

1032x - 408*5 = HCF of these numbers

=> 1032x - 2040 = 24

=> 1032x = 24+2040

=> x = 2064/1032

=> x = 2

So value of x is 2.