Question

HEYA... ☺☺

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.PLZ SOLVE THESE 3 ,INTERESTING QUESTION.
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»»»»OR AGAR NAHI ATE NA TO MAT KAR , BCOZ ONLY FOR GENIUS

Answer 1

Hey here is your answer
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1. C. = pi / 2 cm
2. B. = 2
3. C. = Third
as , Tan and Cot is only positive in third quaderant
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@ajaman........

Answer 2

Hey !!!

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Q. 1 ] Solution

•°• Arc of cirlcle = 2πr¢/360°

here , ¢ = 15°
r = 6cm [given ]

hence , Arc of cirlcle = 2×22/7 × 6 × 15°/360

=> 6×2×π15/360

=> π/2cm

(c) is correct answer

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2nd Q

solution :-

sin¢ + cosec¢ = 2

sin¢ + 1/sin¢ = 2

sin²¢ + 1 = 2sin¢

sin²¢ - 2sin¢ + 1 = 0 {quadratic form ]

sin²¢ - sin¢ - sin¢ + 1 {spliting term]

sin¢(sin¢ - 1 ) - 1 ( sin¢ - 1 )

sin¢ -1 = 0

sin¢ = 1

now , from given question

sin^20 + cosec^20 = ?

sin^20 + 1/sin^20

(1)^20 + (1 )^20

=> 2 Answer ✔

hence , option B is correct answer !!

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Q. 3

sin¢ = - 1/2 , and tan¢ = 1

sin¢ = - sin30°

¢ = -30

and , similarly ,

tan¢ = 1

tan¢ = tan45°

¢ = 45 °

¢ of sin is - and ¢ of tan is +

hence , search that quadrant in which sin is -(ve) and tan is +(ve)

hence , that quadrant is 3rd quadrant

hence , option ( c ) is correct answer !!!

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Hope it helps you ✒

@Rajukumar111