Question

Heya plzz explain well ! will be marked brainliest!

Answer 1

Solution :

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Given :

To find the value of :

$\frac{2^{2001} + 2^{1999}}{2^{2000} - 2^{1998}}$

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⇒ $\frac{2^{2001} + 2^{1999}}{2^{2000} - 2^{1998}}$

⇒ $\frac{2^{2 + 1999} - 2^{1999}}{2^{2 + 1998} - 2^{1998}}$

⇒ $\frac{ 2^{1999}*2^{2} + 2^{1999}}{ 2^{1998}*2^2 - 2^{1998}}$

⇒ $\frac{2^{1999}(2^2 + 1)}{2^{1998}(2^2 - 1)}$

⇒ $\frac{2^{1998 + 1}(4 + 1)}{2^{1998}(4 - 1)}$

⇒ $\frac{2*2^{1998}( 5 )}{2^{1998}(3)}$

⇒ $\frac{2*(5)}{3}$

⇒ $\frac{10}{3}$

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Answer 2

Nice question mate!!!✌✌✌

Ur answer goes like this.....

》2^2001 + 2^1998/2^2000 - 2^1998

》2^1998(2^3+2^1)/2^1998(2^2-2^1)

Cancelling 2^1998

》8+2/4-2

》 10/3


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