how many slabs of cement are required to tile a platform of length 8m are breath 6m,if the length of each slabs is 4cm are breath 3 cm
Answers
Answered by
153
Area of platform to be tiled [ Length=8m,Breadth=6m] = 48m² =480000cm²
Area of cement slab [ Length=4cm ,Breadth =3cm ] = 4×3=12cm²
Number of cement slabs required to tile the platform are 480000/12=40,000
Therefore,40,000 slabs are required .
Area of cement slab [ Length=4cm ,Breadth =3cm ] = 4×3=12cm²
Number of cement slabs required to tile the platform are 480000/12=40,000
Therefore,40,000 slabs are required .
Answered by
85
Answer:
Number of slabs of cement are required to tile a platform are 40000 .
Step-by-step explanation:
Formula
Area of a rectangle = Length × Breadth
As given
Platform of length 8m are breath 6m .
Area of the platform = 8 × 6
= 48 m²
As
1` m = 100 cm
Thus
48 m² = 48 × 100 × 100 cm²
= 480000 cm²
if the length of each slabs is 4cm are breath 3 cm .
Area of a slab = 4 × 3
= 12 cm²
Let us assume that the numbers of slabs of cement are required to tile a platform be x .
Equation becomes
12 × x = 480000
12x = 480000
x = 40000
Therefore the number of slabs of cement are required to tile a platform are 40000 .
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