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... ➡➡➡hey buddy refer attachment
1. volume = 2.56÷1.5= 1.69~~ 1.61L
2.
1. volume = 2.56÷1.5= 1.69~~ 1.61L
2.
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35.
NO. OF MOLECULES=NO. OF MOLES X AVAGADROS NO. AVAGADRO NO. IS 6.022 X 10^23
NO. OF MOLES = 10^25/6.022 X 10^23...........................(1)
NO. OF MOLES ALSO EQUAL TO= MASS / MOLECULAR MASS...............................(2) MOLECULAR MASS OF CCL4 IS 12+4 X 35.5=142+12=154
FROM USING (1) AND (2) GET THE VALUE OF MASS NOW DENSITY = 1.5gm/ml
DENSITY = MASS/VOLUME...................(3) YOU KNOW THE VALUE OF MASS AND DENSITY SUBSTITUTE THOSE VALUES IN EQUATION (3) AND GET YOUR ANSWER WHICH WILL BE ''ml''
36.
since the percentage is .86%.therefore
in 100 gm of starch molecule will contain .86 gm of phosphorus
given 1atom of phosphorus is contaoned in one molecule.
therefore Na(avagadro no) of phosphorus will also contain Na molecule or 1mole which corresponds to molecular mass.
.86 gm of phosphorus equal to 100 gm of molecule
31 gm corresponds to 100×31/.86=3604.5gm
average molecular mas=3604.5
37.
I microgram means 1 x 10>-6 gm
Now 12 gm carbon = 6.023 x 10>23 atoms
1 x 10> -6 gm = 6.023 x 10>23 / 12 x 1 x 10> -6
= 5.019 x 10 >16
38.
Molarity= (number of moles of that substance) / (Volume of solution in litres)
7= (number of moles of HCl) / 0.05
Thus,
Number of moles of HCl = 7 x 0.05 = 0.35
The number of moles of HCl will remain unchanged.
Now, for new solution,
0.35= 0.35 / (New volume of solution in litres)
Thus,
New volume = 1 litre
Thus, amount of water added = 1- 0.05 litre = 0.95 litre = 950 ml
NO. OF MOLECULES=NO. OF MOLES X AVAGADROS NO. AVAGADRO NO. IS 6.022 X 10^23
NO. OF MOLES = 10^25/6.022 X 10^23...........................(1)
NO. OF MOLES ALSO EQUAL TO= MASS / MOLECULAR MASS...............................(2) MOLECULAR MASS OF CCL4 IS 12+4 X 35.5=142+12=154
FROM USING (1) AND (2) GET THE VALUE OF MASS NOW DENSITY = 1.5gm/ml
DENSITY = MASS/VOLUME...................(3) YOU KNOW THE VALUE OF MASS AND DENSITY SUBSTITUTE THOSE VALUES IN EQUATION (3) AND GET YOUR ANSWER WHICH WILL BE ''ml''
36.
since the percentage is .86%.therefore
in 100 gm of starch molecule will contain .86 gm of phosphorus
given 1atom of phosphorus is contaoned in one molecule.
therefore Na(avagadro no) of phosphorus will also contain Na molecule or 1mole which corresponds to molecular mass.
.86 gm of phosphorus equal to 100 gm of molecule
31 gm corresponds to 100×31/.86=3604.5gm
average molecular mas=3604.5
37.
I microgram means 1 x 10>-6 gm
Now 12 gm carbon = 6.023 x 10>23 atoms
1 x 10> -6 gm = 6.023 x 10>23 / 12 x 1 x 10> -6
= 5.019 x 10 >16
38.
Molarity= (number of moles of that substance) / (Volume of solution in litres)
7= (number of moles of HCl) / 0.05
Thus,
Number of moles of HCl = 7 x 0.05 = 0.35
The number of moles of HCl will remain unchanged.
Now, for new solution,
0.35= 0.35 / (New volume of solution in litres)
Thus,
New volume = 1 litre
Thus, amount of water added = 1- 0.05 litre = 0.95 litre = 950 ml
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