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Given :-
- Vertices ↪(±6 ,0)
- Foci ↪(±2√10,0)
To Find :-
- The equation of hyperbola.
Solution :-
↪The equation will have the form :
↪Given that, The vertices are (0,±6) :
↪Here, a = 6 , a² = 6² = 36.
.°. a² = 36.
↪Given that, The foci are (±2√10,0)
↪Here, c = 2√10 , c² = (2√10)² = 4 × 10 = 40.
.°. c² = 40.
Now, we know that,
↪b² = c² - a²
↪ b² = 40 - 36
↪ b² = 4
.°. b² = 4.
Hence,
↪The equation of hyperbola is :
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