Physics, asked by sindhushareddy101, 6 months ago

how to prove GMm/R^2=m(2πR)^2/t^2R

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Answered by viiiakajal9

Answer:

Let's derive it for a circular orbit, assuming a mass m is orbiting a mass M, ... v = 2πr / T. This gives GM/ r = 4π2r2/T2. Re-arranging gives: Kepler's Third

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how to prove GMm/R^2=m(2πR)^2/t^2R​

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how to prove GMm/R^2=m(2πR)^2/t^2R