Question

❥Heya ❥

$\huge \pink \star{ \green{ \boxed{ \boxed{ \boxed{ \purple{ \mathfrak{Question :}}}}}}} \pink\star$

❍ A father is twice as old as his son. He was 6 times his son’s age 20 years ago. What is the father’s present age ?

❍ A mother is 21 years older than her child. In exactly 6 years from now, the mother will be exactly 5 times as old as the child. Where's the father ?

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AN⛎SHA ❤✌❄☺​

Answer 1

Answer:

1. A father is twice as old as his son. He was 6 times his son’s age 20 years ago. What is the father’s present age?

Solution :

Let the Son age be a and Father age be 2a

• According to the Question :

⇒ 20 years ago Father was 6 times of son

⇒ (Father - 20) = 6 × (Son - 20)

⇒ (2a - 20) = 6 × (a - 20)

⇒ 2a - 20 = 6a - 120

⇒ 120 - 20 = 6a - 2a

⇒ 100 = 4a

• Dividing both by 4

⇒ a = 25 years 〔 Son Age 〕

• Father's Present Age :

⇒ Father = 2a

⇒ Father = 2(25 years)

⇒ Father = 50 years

∴ Father's Present Age is 50 years.

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2. A mother is 21 years older than her child. In exactly 6 years from now, the mother will be exactly 5 times as old as the child. Where's the father?

Solution :

Let's the Child's age be n and Mother's age be (n + 21)

• According to the Question :

⇒ 6 years from now Mother will be 5 times of Son

⇒ (Mother + 6) = 5 × (Son + 6)

⇒ (n + 21) + 6 = 5 (n + 6)

⇒ n + 27 = 5n + 30

⇒ 27 - 30 = 5n - n

⇒ - 3 = 4n

⇒ - 3/4 = n

• Changing it into months

⇒ - 3/4 × 12 = n

⇒ - 3 × 3 = n

⇒ n = - 9 months

The child is not born and after 9 months child will be born, & you know the answer where is father maybe making love xD.

Answer 2

✒️QUESTION✒️

➊ A father is twice as old as his son. He was 6 times his son’s age 20 years ago. What is the father’s present age ?

✒️ANSWER✒️

⚘GIVEN:

• A Father's age is twice of the son's age.
• 20 years ago The Father's age was 6 times of the son's age

⚘FIND:

• Present age of Father = ?

⚘SOLUTION:

Let, the present age of Father be x years

and the son's age be y years

Now,

$\mathbb{ \green{ACCORDING \: TO \: QUESTION}}$

x = 2y ............(i)

x - 20 = 6(y-20)

=> x - 20 = 6y -120

=> x - 20 + 120 = 6y

=> x + 100 = 6y ..........(ii)

Now, in eq(i)

x = 2y

put this value in eq(ii)

x + 100 = 6y

=> 2y + 100 = 6y

collect like terms

=> 100 = 6y - 2y

=> 100 = 4y

$\bold{ =>y = \frac{100}{4} }$

$\bold{ =>y = \frac{ \cancel{100}}{ \cancel{4}} = 25 }$

So, y = 25

Substitute this value in eq(i)

x = 2y

=> x = 2(25)

=> x = 50

Hence, Present age of Father = x = 50

and, Present age of Son = y = 25

♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡

✒️QUESTION✒️

A mother is 21 years older than her child. In exactly 6 years from now, the mother will be exactly 5 times as old as the child. Where's the father ?

✒️ANSWER✒️

⚘GIVEN:

• A mother is 21 years older than her child.
• After 6 years the mother will be 5times as old as his child.

⚘FIND:

• Where's the father = ?

⚘SOLUTION:

Let, the child's age be x years

So, mothers age will be x + 21 years

$\mathbb{ \red{ACCORDING \: TO \: QUESTION}}$

• 6 years later, mother will be 5 times of his child's age

So,

=> 5(x + 6) = x + 21 + 6

=> 5x + 30 = x + 27

=> 5x - x = 27 - 30

=> 4x = -3

$\bold{ => x = \frac{ - 3}{4} }$

Now, convert it into the months we got

$\bold{ => \frac{ - 3}{4} \times 12}$

$\bold{ => \frac{ - 3}{ \cancel{4}} \times \cancel{12}}$

$\bold{ => - 3 \times 3}$

$\bold{ => - 9}$

Hence, by this we can conclude that the child was not born yet.......

Nd born after 9 months.

So, the father was with the mother of the child.