Question

Heya User,

Answer the Question :-

The dome of a building is in the form of a hemisphere of radius 63 dm. Find the cost if it is to be painted at the rate of Rs 5 per m².

Answer 1

$2\pi r^{2} = 2 \times \frac{22}{7} \times 63 \times 63 \\ \\ \: \: \: \: \: \: \: \: \: \: \sf= 24948 \: dm {}^{3} \\ \\ \\ \sf Painting \: cost \: 5 \: per \: m^{2} \\ \\ = \sf \frac{24948}{100} \times 5 = \red{ Rs. 1247.4}$

Answer 2

⭐Hola User_____________

⭐Here is Your Answer....!!!!

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↪Actually welcome to the concept of the SURFACE AREAS AND VOLUMES

↪Basically we know that ...

↪The Curved Surface area of a hemisphere is given by

↪C.S.A = 2 (PI)R^2

↪Since here the given radius = 63 dm = 63 × 10^-1 m = 6.3 m

↪thus the curved surface area will be as ...

↪c.s.a = 2*(3.14)*(6.3)^2 = 6.28*(6.3)^2 = 249.25 m^2

↪Thus the area to be painted on the dome = 249.25 m^2

↪COST

↪NOW talking about the cost ...

↪we actually know that ...

↪Cost = Rate * Area

↪thus substituing we get as

↪COST OF PAINTING = 5 * (249.25) = 1246.25 rupees

↪thus the cost of painting the dome is Rs. 1246.25 /-

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