The sum of first three numbers in an arithmetic progression is 18. If the product of the first and the third term is 5 times the common difference, find the three numbers.
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Answered by
4
here is the A.P
hope it helps :)
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Anonymous:
i posted the question
oh ok
do u got the
correct answer
no
oh
I also not still
s sorry plz report my answer
U have added instead of multiplying
hmm i have rectified it i m sorry
Answered by
5
Answer:
Step-by-step explanation:
a1 +a2+a3=18
&
A1*a3=5d
A+a+d+a+2d=18
=>3a+3d=18
=>a+d=6
=>a=6-d
A(a+2d)=5d
asquare+2ad=5d
=>(6-d)square+2d(6-d)=5d
=>36+dsquare-12d+12d-2dsquare=5d
=>dsquare+5d-36=0
On solving the equation using x,
D=4 or - 9
So,a=2or15
Therforw the numbers are 2,6,10 or 15,6,-3
Hope it helps
What is the correct answer actually ??I have got a=6 and d=36/7...???what is the correct answer
My answer is coorect and it is verified
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