Question

Heya User!!!

Need ur help!!!

What will be the volume occupied by 3.011*10^20 molecules of water vapour at STP??

#No Spam

Answer 1

Answer:

at stp:

temperature is 273 k

and

p = 1 atm

now

solve

1 mol --------------------> 6.022 X 10^23 molecules

3 .011 X 10^20 molecules ---------------> 1 divided by 6.022 X 10^23 and multipled by 3.011 X 10 ^20 molecules

=0.5 X 10^-3 mol

now

pv = nrt

1 X V = 0.5 X 10^-3 X 0.0821 X 273

so

V= 11.2 X 10^-3 L