Question

Heyaa

A metal cube of edge 6 cm is melted and formed into three smaller cubes. If the edges of two smaller cubes are 3cm and 4cm respectively, find the edge of the third smaller cube.

#Urgently needed

Answer 1

Answer :-

Step by step explanation :-

If in any question we have word melted than we have to take volume.

If in any question we have word melted than we have to take volume.Volume of cube :-

$= {a}^{3} \\ = {6}^{3} \\ \\ = 216 {cm}^{3}$

Volume of three cubes are equal to volume of big cube.

$216 = {4}^{3} + {3}^{3} + {x}^{3} \\ \\ 216 - 91 = {x}^{3} \\ \\ {x}^{3} = 125 \\ \\ x = 5 \: cm$

Answer is $\color{Red}{5~cm}$

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mark as brainliest answer.

Answer 2

Answer:

= 5 m

Step-by-step explanation:

Given :

Edge of a bigger cube (R)= 6 m

Edge of a first smaller cube(r²)= 3 m

Edge of a second smaller cube(r2)= 4 m

Volume of a cube = side³

Volume of a bigger cube(V) = (sides)³

= (6)³= 216 m³

It is melted into three other cubes ,so the volume of the smaller cubes remains same as the volume of bigger cube .

volume of the first smaller cubes(V1)= (3)³=27 m³

volume of second smaller cube(V2) = 4³ = 64 m³

Total volume(V) = volume of first smaller cube(V1) + volume of second smaller cube(V2)+ + volume of third smaller cube(V3)

V= V1+V2+V3

216  = 27 +64 +V3

216 = 91 + V3

216 -  91 = V3

125 = V3

volume of third cube = 125 m³

Edge³= 125

Edge = ³√125

Edge =³√5×5×5

Edge= 5m

Hence, the edge of the third cube is = 5 m