Question

heyaa....

❤only maths geniues❤

step by step explanation

don't copy❌

#Dramaqueen⭐

Answer 1

A (-1,2 )=x1 , y1

B (3,2)=x2 , y2

By distance formula

AB =√(x2-x1) square+( y2-y1)square

=√(3- (-2)) square + ( 2-2 ) square

=√ ( 3 + 2 ) square + (0) square

=√ (5) square + 0

=√ 5×5 + 0

=√ 25 +0

=√ 25

AB = 5

if like this answer mark me as branilist or give heart mark or follow me

Answer 2

Answer:

(1,0) and (1,4)

Step-by-step explanation:

Let A(-1,2) and C(3,2) be the two opposite vertices and vertex B be (x,y).

Since ABCD is a square, AB = BC.

⇒ AB² = BC²

⇒ (x + 1)² + (y - 2)² = (x - 3)² + (y - 2)²

⇒ x² + 1 + 2x + y² + 4 - 4x = x² + 9 - 6x + y² + 4 - 4x

⇒ x² + 2x + y² - 4x - x² + 6x - y² + 4x = 8

⇒ 8x = 8

⇒ x = 1.

As ABCD is a square, ∠B = 90°.

⇒ AB² + BC² = AC²

⇒ (x + 1)² + (y - 2)² + (x - 3)² + (y - 2)² = (3 + 1)² + (2 - 2)²

⇒ x² + 1 + 2x + y² + 4 - 4y + x² + 9 - 6x + y² + 4 - 4y = 16

⇒ 2x² - 4x + 10 + 2y² - 8y + 8 = 16

⇒ 2(1)² - 4(1) + 10 + 2y² - 8y + 8 = 16

⇒ 2 - 4 + 10 + 2y² - 8y + 8 = 16

⇒ 2y² - 8y = 0

⇒ y² - 4y = 0

⇒ y(y - 4) = 0

⇒ y = 0,4.

Therefore, the other two vertices of square are (1,0) and (1,4).

Hope it helps!