Water is flowing through a cylindrical pipe of internal diameter 3 cm into a cylindrical tank of base diameter 40 cm,at the rate of 0.24 m/s. Determine the rise in the level of water in tank in half an hour.
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Answer:
60.75 cm
Step-by-step explanation:
Given, diameter of cylindrical pipe = 3 cm.
So, the radius of the cylindrical pipe = 1.5 cm.
Given, diameter of cylindrical tank = 40 cm.
Then, radius of cylindrical tank = 20 cm.
Height of circular pipe = 0.24 m/s = 24 cm/s.
Now, Volume of water flows in 1 second = πr²h
= 3.14 * (1.5)² * 24
= 169.56
Now, Volume of water flows in 1/2 hour(30 minutes)
= 169.56 * 30 * 60
= 305208
∴ Volume of water flows = volume of cylinder
⇒ 305208 = πr²h
⇒ 305208 = 3.14 * (20)² * h
⇒ 305208 = 5024 * h
⇒ h = 60.75 cm.
Therefore, Level of water in the tank is 60.75 cm.
Hope it helps!
is it correct?
I don't really know,when I solved it,I got 243 cm
Try it this way...volume of pipe equals volume of tank and substitute values
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