Heylo
Again
Please
Solve
The
Question
Because
I'm
Near
Of
Murdering
This
Chapter
As
Well
As
The
Book
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Answers
Answered by
2
sin theta = cos theta
As theta is acute
So theta = 45
2 tan^2 the ta +sin^2 -1
2 + 1/2. -1
3/2
As theta is acute
So theta = 45
2 tan^2 the ta +sin^2 -1
2 + 1/2. -1
3/2
Answered by
10
Answer:
heyy mate!!1 here is ur answer
gven, sin theta=cos theta
sin theta/cos theta=1
tan theta =1
therefore, theta =45 degree
2 tan^2 theta+sin^2 theta-1
2* tan^2 45 degree + sin ^2 degree-1
2* 1^2 +( 1/root over 2)^2 -1
2+1/2-1
(4+1-2)/2
=3/2
hope it will help u :)
if it is then plz mark mine answer as the brainliest one
yah me to agree with u and want murder this chapter......xD
becoz me too following this book
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