Question

heyy guys!!!
find a cubic polynomial with the sum, sum of product of its zeros taken two at a time and product of zeros as -7 ,- 14 respectively.​

Answer 1

Answer:

let the polynomial be ax3+ bx2 + cx+d and zeros of $\alpha,\beta,\gamma</p><p></p><p>\alpha + \beta + \gamma = - ( - 2)/1 = 2 = - b/a \\ \alpha \beta + \beta \gamma + \gamma \alpha = - 7 = - 7/1 = ca \\ \alpha \beta \gamma = - 14 = - 14/1 = da \\ a = b= - 2 \\c = - 7 \\ d = 14$