Question

If a-b =6, a×b=-3 then find a^3-b^3

Answer 1

Step-by-step explanation:

A^3-b^3

=(a-b)(a^2+b^2+a*b)

=(a-b)((a-b)^2+2*ab +a*b)

=6(36 +40 +20)

=6*96

=576

Answer 2

Answer:

a^3-b^3=162

Step-by-step explanation:

Given,

a-b=6

ab=-3

$(a-b)^3=6^3\\a^3-b^3-3ab(a-b)=216\\a^3-b^3-3(-3)(6)=216\\a^3-b^3=216-54=162$