Heyy mate...
Que:-
Two Dice are thrown at the Same time and the product of number appearing on them is noted.
Then Find the probability that the product is a prime Number.
by:- AJ.
Answers
Answered by
17
Maximum outcomes will be ;- 36
Possible outcomes as the product of prime Number ;- (1,2) , (1,3) , (1,5), (5,1), (3,1), (2,1)
So,,
Probability of getting product of prime Number
6/36= 1/6 answer
Thanks me Later ❤️
Possible outcomes as the product of prime Number ;- (1,2) , (1,3) , (1,5), (5,1), (3,1), (2,1)
So,,
Probability of getting product of prime Number
6/36= 1/6 answer
Thanks me Later ❤️
Answered by
13
Heyy Buddy ❤
here's your Answer ...
☆ Total Number of Possible Outcome = 6 × 6
=> 36.. The Observation are;
[ (1,1) (1,2)(1,3)(1,4)(1,5),(1,6)
(2,1)(2,2)(2,3)(2,4),(2,5)(2,6)
(3,1)(3,2)(3,3),(3,4),(3,5)(3,6)
(4,1)(4,2)(4,3),(4,4)(4,5)(4,6)
(5,1)(5,2)(53)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,6)]
For The Favourable Outcomes it has to be the prime number, so
=> (1,2)(2,1)(1,3)(3,1)(5,1)(1,5)
=> Favourable Outcomes = 6.
Therefore,
Probability of getting the product of prime Number = Favourable Outcomes/ Total Outcome
=> P = 6/36
=> Probability = 1/6
✔✔
here's your Answer ...
☆ Total Number of Possible Outcome = 6 × 6
=> 36.. The Observation are;
[ (1,1) (1,2)(1,3)(1,4)(1,5),(1,6)
(2,1)(2,2)(2,3)(2,4),(2,5)(2,6)
(3,1)(3,2)(3,3),(3,4),(3,5)(3,6)
(4,1)(4,2)(4,3),(4,4)(4,5)(4,6)
(5,1)(5,2)(53)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,6)]
For The Favourable Outcomes it has to be the prime number, so
=> (1,2)(2,1)(1,3)(3,1)(5,1)(1,5)
=> Favourable Outcomes = 6.
Therefore,
Probability of getting the product of prime Number = Favourable Outcomes/ Total Outcome
=> P = 6/36
=> Probability = 1/6
✔✔
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