Math, asked by PreciouStone, 1 year ago

✌️✌️☺️heyyy guys ☺️✌️✌️



HERE IS A QUESTION FOR YOU ALL



♨️PQRS is a square of side 4 cm , from each corner a quadrant of radius 1 cm is cut ... find the area of the remaining square ...♨️





Answers

Answered by deepsen640
1

Answer:

Area of remaining part = 90/7 cm²

Step-by-step explanation:

Given that,

the side of square = 4 cm

so,

its area = 4 × 4

= 16 cm²

Now,

four quadrants has removed from it each of radius = 1 cm

4 equal quadrants = 1 circle

so,

area of 4 quadrants = πr²

= 22/7 × 1 × 1

= 22/7 cm²

so,

Area of the remaining part

= 16 - 22/7

= 90/7 cm²

Area of remaining part = 90/7 cm²

Answered by singlesitaarat31
2

\red {HELLO\:DEAR}

✌️ \huge{ \boxed{ \underline{ \bf \red{ANSWER}}}}]✌️

Answer: area of square = a²

= 4*4= 16 cm²

Area of 4 quadrant of same radius = area of one circle

=πr²

= 3.14*1*1

= 3.14

Area of remaining square = area of square - area of the 4 quadrants

= 16 - 3.14

= 12.86 cm²

Mark it as a brainliest answer

\green {VISHU\:PANDAT}

\blue {FOLLOW\:ME}

Similar questions