Heyyy guys plzzz help me in doing this question------->
ABC is a right angled at C. If BC=a, CA=b and AB =c and p is the length of perpendicular drawn from CAB, then prove that : 1) pc=ab, 2) 1/p^2=1/a^2+1/b^2
Shrutika123:
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Step-by-step explanation:
1.Area is 1/2 base * height . So for the same triangle area can be 1/2*b*a and can be 1/2*p*c. Hence cp = ab
2 . From above p2 = a2b2/c2
1/p2 = c2/ a2b2
but for right triangle c2 = a2 +b2
Hence 1/p2 = (a2+b2)/ a2b2
Hence 1/p2 = 1/a2+1/b2
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