HgCl2 and I2 both when dissolved in water containing I ions
the pair of species formed is : [2017]
(a) HgI₂, I⁻ (b) HgI₄²⁻ , I₃⁻
(c) Hg₂I₂, I⁻ (d) HgI₂ , I₃⁻
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The pair of species formed is HgI4^-2 + 2 Cl-
Option (D) is correct.
Explanation:
HgCl 2 and I 2 both when dissolved in water containing I − ions the pair of species formed is HgI4^2-, I3^-
I2 + I- -----> I3 −
HgCl2 + 4I- -----> HgI4^-2 + 2 Cl-
Thus the pair of species formed is HgI4^-2 + 2 Cl-
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