Hi ..ansewr pls a question of chemistry class 12 chapter solutions
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heya.
given, Molality =0.195 m,
Let take mass of solvent (water) = 1 kg
Use above formula we get
Moles of solute = 0.195 mol
Molar mass of water (H2O ) = 2 × 1 + 16 = 18
Mass of water (mass of solvent 1 kg = 1000 g
Number of moles of water = 1000 g / 18 = 55.56 mol
Use above formula we get
Mole fraction of H2S = 0.195/(0.195 + 55.56) = 0.0035
At STP, pressure (p) = 0.987 bar always
According to Henry’s law:
p = KH × X
KH = p / X = 0.987 / 0.0035 = 282 bar
tysm.@kundan
given, Molality =0.195 m,
Let take mass of solvent (water) = 1 kg
Use above formula we get
Moles of solute = 0.195 mol
Molar mass of water (H2O ) = 2 × 1 + 16 = 18
Mass of water (mass of solvent 1 kg = 1000 g
Number of moles of water = 1000 g / 18 = 55.56 mol
Use above formula we get
Mole fraction of H2S = 0.195/(0.195 + 55.56) = 0.0035
At STP, pressure (p) = 0.987 bar always
According to Henry’s law:
p = KH × X
KH = p / X = 0.987 / 0.0035 = 282 bar
tysm.@kundan
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