Question

hi answer my question please .


the length of the two parallel sides of a Trapezium are 15 cm and 10cm . if its area is 100 sq.cm. find the distance between the parallel sides.

Answer 1

Hey friend here is your answer.....


Solution :-

Given :

a = 15 cm , b = 10 cm , Area = 100 sq.cm.


Area of the trapezium = 100


$\frac{1}{2} \times \: (a + b) \: = \: 100$

$\frac{1}{2} \times h \times (15 + 10) \: = \: 100$

$h \times 25 = 200$

$h = \frac{200}{25} = 8$


Therefore the distance between the parallel sides = 8 cm .



Hope it helps you.....

Answer 2

Heya!!

_____________________________________

Given,

➡️Two parallel sides

• a = 15 cm
• b = 10 cm

➡️ Area = 100 sq.cm.

To Find:-

▶️Distance between the parallel sides.

Calculations:-

Area of trapezium = 100

$\frac{1}{2}$ × some of parallel sides × height=100

$\frac{1}{2 } \times (a + b)×h = 100$

$\frac{1}{2} \times h \times (15 + 10) = 100$

h×25=100×2

h × 25 = 200

$h = \frac{200}{25}$

h =8

Therefore the distance between the parallel sides = 8 cm .