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if x = 2 + √3 , find x² + 1/x².
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Hey there !
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Given :
x = 2 + √3
1/x = 1/ 2 + √3 × 2 - √3/2-√3
1/x = 2 - √3 / 2² - √3²
1/x = 2 - √3 / 4 - 3
1/x = 2 - √3
Now,
x + 1/x = 2 + √3 + 2 - √3
x + 1/x = 2 + 2
x + 1/x = 4
Squaring both sides ;
( x + 1/x)² = (4)²
=> x² + 1/x² + 2 = 16
=> x² + 1/x² = 16 - 2
=> x² + 1/x² = 14
Thanks for the question!
diya27699:
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