Question

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Answer 1

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Answer 2

taking L.H.S:-

√[(1-cosA)²/(1²-cos²A)],

√[(1-cosA)²/sin²A],

(1-cosA)/sinA,

1/sinA - cosA/sinA,

cosecA - cotA,



taking R.H.S:-

cosecA-cotA,

[(cosecA-cotA)(cosecA+cotA)]/(cosecA+cotA),

(coeec²A-cot²A)/(cosecA+cotA),

1/(cosecA+cotA),

multiply by sinA in numerator and denominator,

sinA/(1+cosA),

√[sin²A/(1+cosA)²],

√[(1-cos²A)/(1+cosA)²],

√[(1-cosA)/(1+cosA)]