hi can u help me
25. Divide 3600 into two parts such that if one part be lent at 9% per annum and the othera
10% per annum, the total annual income is 333.
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Answer:
let one part be x, then other part is (3600 -x)
Case 1: SI = (x *9 *1) /100
=> SI =9x/100
Case 2: SI =[(3600-x)*10*1/100
=> SI = (3600-x)/10
according to problem,
9x/100 + (3600-x)/10 = 333
or, (9x + 36000-10x) = 33300 or, -x + 36000= 33300 or, x- 36000-33300
or x=2700
two parts are 2700 and 900
Step-by-step explanation:
- hopes it helps you
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