Hi,
Can you solve this doubt:
Of the three numbers, the first is 60% more than the second and 20% less than the third .By how much percentage is the third more than the sec second ?
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Answer:
Two numbers are 20 % and 25 % less than a third number respectively. How much % is the second number less than the first?
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ANSWER
Let the third number be 100.
First number = 80.
Second number = 75
∴ Required % =
80
80−75
×100
=
80
5
×100=6
4
1
%
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