Hi frends plz slove this urgent
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Step-by-step explanation:
E is mid-point
CE = 1/2 CA
but BD = CE
and BD ll CA, so BD ll CE
BDEC is parallelogram
ar(BDC) = ar(EBC) [triangles between same lls and on same base have equal area]
BE is median of ABC,
ar(EBC) = 1/2 ar(ABC)
THUS, ar(BDC) = 1/2 ar(ABC)
finally, 2ar(BDC) = ar(ABC)
pd7309454665:
thanku
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